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Class 9 Mathematics
Chapter 3 Solutions — The World of Numbers
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Overview
Step-by-step NCERT solutions for The World of Numbers (Chapter 3, NCERT Class 9 Mathematics) — the full working for every question, not just the final answer. You can also read the The World of Numbers textbook chapter.
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What these solutions cover
All 43 questions in The World of Numbers are solved in the PDF. Here's what's inside, exercise by exercise:
Natural Numbers and Early Counting Systems
- A merchant in the port city of Lothal is exchanging bags of spices for copper ingots. He receives 15 ingots for every 2 bags of spices. If he brings 12 bags of spices to the market, how many copper ingots will he leave with?
- Look at the sequence of numbers on one column of the Ishango bone: 11, 13, 17, 19. What do these numbers have in common? List the next three numbers that fit this pattern.
- We know that Natural Numbers are closed under addition (the sum of any two natural numbers is always a natural number). Are they closed under subtraction? Provide a couple of examples to justify your answer.
- *Ancient Indians used the joints of their fingers to count, a practice still seen today. Each finger has 3 joints, and the thumb is used to count them. How many can you count on one hand? How does this relate to the ancient base-12 counting systems?
Integers and Brahmagupta's Laws
- The temperature in the high-altitude desert of Ladakh is recorded as 4 °C at noon. By midnight, it drops by 15 °C. What is the midnight temperature?
- A spice trader takes a loan (debt) of ₹850. The next day, he makes a profit (fortune) of ₹1,200. The following week, he incurs a loss of ₹450. Write this sequence as an equation using integers and calculate his final financial standing.
- Calculate the following using Brahmagupta's laws:
- (i) (−12) × 5
- (ii) (−8) × (−7)
- (iii) 0 − (−14)
- (iv) (−20) ÷ 4
- Explain, using a real-world example of debt, why subtracting a negative number is the same as adding a positive number (e.g., 10 − (−5) = 15).
Fractions, Rational Numbers, and Their Arithmetic
- Prove that the following rational numbers are equal:
- (i) 2/3 and 4/6
- (ii) 5/4 and 10/8
- (iii) −3/5 and −6/10
- (iv) 9/3 and 3
- Find the sum:
- (i) 2/5 + 3/10
- (ii) 7/12 + 5/8
- (iii) −4/7 + 3/14
- Find the difference:
- (i) 5/6 − 1/4
- (ii) 11/8 − 3/4
- (iii) −7/9 − (−2/3)
- Find the product:
- (i) 2/3 × 3/10
- (ii) 7/11 × 5/8
- (iii) −4/7 × 5/14
- Find the quotient:
- (i) 2/3 ÷ 3/10
- (ii) 7/11 ÷ 5/8
- (iii) −4/7 ÷ 5/14
- Show that: (1/2 + 3/4) × 8/3 = 1/2 × 8/3 + 3/4 × 8/3.
- Simplify the following using the distributive property: 7/9 × (6/7 − 3/4).
- Find the rational number x such that: 5/6 (x + 3/5) = 5/6 · x + 1/2.
Representation of Rational Numbers on the Number Line
- Represent the rational numbers 2/3, −5/4 and 1(1/2) on a single number line.
- Find three distinct rational numbers that lie strictly between −1/2 and 1/4.
- Simplify the expression: (−1/4) + (5/12).
- A tailor has 15(3/4) metres of fine silk. If making one kurta requires 2(1/4) metres of silk, exactly how many kurtas can he make?
- Find three rational numbers between 3.1415 and 3.1416.
- *Can you think of other way(s) to find a rational number between any two rational numbers?
Decimal Expansions, Cyclic Numbers, and Irrational Numbers
- Without performing long division, determine which of the following rational numbers will have terminating decimals and which will be repeating: 7/20, 4/15 and 13/250. Then check your answers by explicitly performing the long divisions and expressing these rational numbers as decimals.
- Perform the long division for 1/13. Identify the repeating block of digits. Does it show cyclic properties if you evaluate 2/13? Now compute 3/13, 4/13, etc. What do you notice?
- Classify the following numbers as rational or irrational:
- (i) √81
- (ii) √12
- (iii) 0.33333…
- (iv) 0.123451234512345…
- (v) 1.01001000100001…
- (vi) 23.560185612239874790120. Find the explicit fractions in case they are rational.
- The number 0.(9) (which means 0.99999…) is a rational number. Using algebra (let x = 0.(9), multiply by 10, and subtract), explain why 0.(9) is exactly equal to 1.
- *We have seen that the repeating block of 1/7 is a cyclic number. Try to find more numbers (n) whose reciprocals (1/n) produce decimals with repeating blocks that are cyclic.
Exercises
- Convert the following rational numbers into a terminating decimal or a non-terminating and repeating decimal, whichever the case may be, by the process of long division:
- (i) 3/50
- (ii) 2/9
- Prove that √5 is an irrational number.
- Convert the following decimal numbers into the form p/q:
- (i) 12.6
- (ii) 0.0120
- (iii) 3.052
- (iv) 1.235
- (v) 0.23
- (vi) 2.05
- (vii) 2.125
- (viii) 3.125
- (ix) 2.1625
- Locate the following rational numbers on the number line:
- (i) 0.532
- (ii) 1.15
- Find 6 rational numbers between 3 and 4.
- Find 5 rational numbers between 2/5 and 3/5.
- Find 5 rational numbers between 1/6 and 2/5.
- If x/3 + x/5 = 16/15, find the rational number x.
- Let a and b be two non-zero rational numbers such that a + 1/b = 0. Without assigning any numerical values, determine whether ab is positive or negative. Justify your answer.
- A rational number has a terminating decimal expansion whose last non-zero digit occurs in the 4th decimal place. Show that such a number can be written in the form p/10⁴, where p is an integer not divisible by 10. Is it necessary that the denominator of this rational number, when written in the lowest form, is divisible by 2⁴ or 5⁴? Give reasons.
- Without performing division, determine whether the decimal expansion of 18/125 is terminating or non-terminating. If it terminates, state the number of decimal places.
- A rational number in its lowest form has denominator 2³ × 5. How many decimal places will its decimal expansion have? Explain your answer.
- Let a = 7/12 and b = 5/6. Express both a and b in the form k₁/m and k₂/m where k₁, k₂ and m are integers and k₂ – k₁ > 6. Using the same denominator m, write exactly five distinct rational numbers lying between a and b keeping an integer numerator. Explain why the condition k₂ – k₁ > n + 1 is necessary to find n such rational numbers between the two rational numbers a and b using this method.
- Three rational numbers x, y, z satisfy x + y + z = 0 and xy + yz + zx = 0. Show that all the rational numbers x, y, z must be simultaneously zero.
- Show that the rational number (a + b)/2 lies between the rational numbers a and b.
- Find the lengths of the hypotenuses of all the right triangles in Fig. 3.14, which is referred to as the square root spiral.
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