Back to Ganita Manjari Get the App
Class 9 Mathematics
Chapter 4 Solutions — Exploring Algebraic Identities
Open Solutions PDFReads in your browser→Also seeTextbook page→Solutions
Overview
Step-by-step NCERT solutions for Exploring Algebraic Identities (Chapter 4, NCERT Class 9 Mathematics) — the full working for every question, not just the final answer. You can also read the Exploring Algebraic Identities textbook chapter.
Solved
What these solutions cover
All 25 questions in Exploring Algebraic Identities are solved in the PDF. Here's what's inside, exercise by exercise:
Visualising Identities — using (a + b)² = a² + 2ab + b²
- Using the identity (a + b)² = a² + 2ab + b², expand the following:
- (i) (7x + 4y)²
- (ii) (7x/5 + 3y/2)²
- (iii) (2.5p + 1.5q)²
- (iv) (3s/4 + 8t)²
- (v) (x + 1/(2y))²
- (vi) (1/x + 1/y)²
- Using the same identity (a + b)² = a² + 2ab + b², find the values of:
- (i) (64)²
- (ii) (105)²
- (iii) (205)²
Factorisation Using (a + b)² and (a − b)² Identities
- Factor completely:
- (i) 9x² + 24xy + 16y²
- (ii) 4s² + 20st + 25t²
- (iii) 49x² + 28xy + 4y²
- (iv) 64p² + (32/3)pq + (4/9)q² *(v) 3a² + 4ab + (4/3)b² *(vi) (9/5)s² + 6sv + 5v²
- Find the values of the following using the identity (a − b)² = a² − 2ab + b²:
- (i) (79)²
- (ii) (193)²
- (iii) (299)²
More Identities — (a + b + c)² and (a − b)²
- Find the following squares using one of the above identities. Determine which identity makes each calculation easier.
- (i) 117²
- (ii) 78²
- (iii) 198²
- (iv) 214²
- (v) 1104²
- (vi) 1120²
- Factor using suitable identities:
- (i) 16y² − 24y + 9
- (ii) (9/4)s² + 6st + 4t²
- (iii) m²/9 + mk/3 + k²/4 + 3nk + 2mn + 9n²
- (iv) p²/16 − 2 + 16/p²
- (v) 9a² + 4b² + c² − 12ab + 6ac − 4bc
- Expand the following using the identity (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca:
- (i) (p + 3q + 7r)²
- (ii) (3x − 2y + 4z)²
- Is this an identity? (a + b − c)² + (a − b + c)² + (a − b − c)² = 2a² + 2b² + 2c²
Factorisation Using (x + a)(x + b) = x² + (a + b)x + ab and Related Identities
- Fill in the blanks to complete the following identities:
- (i) s² − 11s + 24 = (___)(___)
- (ii) (___)( x + 1) = 3x² − 4x − 7
- (iii) 10x² − 11x − 6 = (2x − ___)(___ + 2)
- (iv) 6x² + 7x + 2 = (___)(___)
- Select and use the identity that will help you to find the following products without multiplying directly:
- (i) (41)²
- (ii) (27)²
- (iii) 23 × 17
- (iv) (135)²
- (v) (97)²
- (vi) 18 × 29
- (vii) 34 × 43
- (viii) (205)²
- Factor the following:
- (i) 9a² + b² + 4c² − 6ab + 12ac − 4bc
- (ii) 16s² + 25t² − 40st
- (iii) r² − r − 42
- (iv) 49g² + 14gh + h²
- (v) 64u² + 121v² + 4w² − 176uv − 32uw + 44vw
Simplification of Rational Expressions Using Algebraic Identities
- Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
- (i) (3p² − 3pq − 18q²) / (p² + 3pq − 10q²)
- (ii) (n³ − 3n²m + 3nm² − m³) / (5m² − 10mn + 5n²)
- (iii) (w³ − v³ + x³ + 3wvx) / (w² + v² + x² − 2wv − 2vx + 2wx)
- (iv) (4y² − 20yz + 25z²) / (25z² − 4y²)
- (v) (x² + x − 6)(x² − 7x + 12) / ((x² − 6x + 8)(x² − 9))
- (vi) (p⁴ − 16) / (p² − 4p + 4)
Exercises
- Use suitable identities to find the following products:
- (i) (–3x + 4)²
- (ii) (2s + 7)(2s – 7)
- (iii) (p² + 1/2)(p² – 1/2)
- (iv) (2n + 7)(2n – 7)
- (v) (s – 2t)(s² + 2st + 4t²)
- (vi) (1/(2r) – 4r)²
- (vii) (–3m + 4k – l)²
- (viii) (x – y/3)³
- (ix) ((7/2)k – (2/3)m)³
- Find the values using suitable identities:
- (i) 17 × 21
- (ii) 104 × 96
- (iii) 24 × 16
- (iv) 147³
- (v) 199³
- (vi) 127³
- (vii) (–107)³
- (viii) (–299)³
- Factor the following algebraic expressions:
- (i) 4y² + 1 + 1/(16y²)
- (ii) 9m² – 1/(25n²)
- (iii) 27b³ – 1/(64b³)
- (iv) x² + 5x/6 + 1/6
- (v) 27u³ – 1/125 – 27u²/5 + 9u/25
- (vi) 64y³ + z³/125
- (vii) p³ + 27q³ + r³ – 9pqr
- (viii) 9m² – 12m + 4
- (ix) 9x³ – (8/3)y³ + z³/3 + 6xyz
- (x) 4x² + 9y² + 36z² + 12xz + 36yz + 24xy
- (xi) 27u³ – 1/216 – 9u²/2 + u/4
- Simplify the following (assume denominators are not equal to 0):
- (i) (4x² + 4x + 1)/(4x² – 1)
- (ii) 9(3a³ – 24b³)/(9a² – 36b²)
- (iii) (s³ + 125t³)/(s² – 2st – 35t²)
- Find possible expressions for the length and breadth of each of the following rectangles whose areas are given by the following expressions in square units:
- (i) 25a² – 30ab + 9b²
- (ii) 36s² – 49t²
- Find possible expressions for the length, breadth, and height of each of the following cuboids whose volumes are given by the following expressions in cubic units:
- (i) 6a² – 24b²
- (ii) 3ps² – 15ps + 12p
- The village playground is shaped as a square of side 40 metres. A path of width s metres is created around the playground for people to walk. Find an expression for the area of the path in terms of s.
- If a number plus its reciprocal equals 10/3, find the number.
- A rectangular pool has area 2x² + 7x + 3 square hastas. If its width is 2x + 1 hastas, find its length. (Hasta was a unit used to measure length.)
- If both x – 2 and x – 1/2 are factors of px² + 5x + r, show that p = r.
- If a + b + c = 5 and ab + bc + ca = 10, then prove that a³ + b³ + c³ – 3abc = –25.
- By factoring the expression, check that n³ – n is always divisible by 6 for all natural numbers n. Give reasons.
- Find the value of:
- (i) x³ + y³ – 12xy + 64, when x + y = –4
- (ii) x³ – 8y³ – 36xy – 216, when x = 2y + 6
Keep solving
More solutions in Ganita Manjari
Explore
More NCERT Solutions for Class 9
Read the Exploring Algebraic Identities textbook chapter / PDF, or browse all NCERT Class 9 Mathematics solutions.
Solve offline with notes, solutions & mock tests
CBSE Prepmaster — free on iOS & Android