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Class 7 Mathematics
Chapter 7 Solutions — A Tale of Three Intersecting Lines
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Overview
Step-by-step NCERT solutions for A Tale of Three Intersecting Lines (Chapter 7, NCERT Class 7 Mathematics) — the full working for every question, not just the final answer. You can also read the A Tale of Three Intersecting Lines textbook chapter.
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What these solutions cover
All 20 questions in A Tale of Three Intersecting Lines are solved in the PDF. Here's what's inside, exercise by exercise:
Equilateral and Isosceles Triangles
- Use the points on the circle and/or the centre to form isosceles triangles. A single circle is given with its centre marked as a dot.
- Two diagrams are given, each showing two or three circles of the same size. Diagram 1: Two circles with centres A and B. Diagram 2: Three circles with centres A, B, and C arranged so each circle passes through the other two centres. Use the points on the circles and/or their centres to form isosceles and equilateral triangles.
Triangle Inequality — Are Triangles Possible for Any Lengths?
- We checked by construction that there are no triangles having sidelengths 3 cm, 4 cm and 8 cm; and 2 cm, 3 cm and 6 cm. Check if you could have found this without trying to construct the triangle.
- Can we say anything about the existence of a triangle for each of the following sets of lengths?
- (a) 10 km, 10 km and 25 km
- (b) 5 mm, 10 mm and 20 mm
- (c) 12 cm, 20 cm and 40 cm
- For each set of lengths seen so far, you might have noticed that in at least two of the comparisons, the direct length was less than the sum of the other two (if not, check again!). For example, for the set of lengths 10 cm, 15 cm and 30 cm, there are two comparisons where this happens. Identify them, and identify the comparison where it does not happen.
Triangle Inequality — Which Lengths Form a Triangle?
- Which of the following lengths can be the sidelengths of a triangle? Explain your answers. Note that for each set, the three lengths have the same unit of measure.
- (a) 2, 2, 5
- (b) 3, 4, 6
- (c) 2, 4, 8
- (d) 5, 5, 8
- (e) 10, 20, 25
- (f) 10, 20, 35
- (g) 24, 26, 28
Triangle Inequality — Conclusion and Third Side Range
- Check if a triangle exists for each of the following set of lengths:
- (a) 1, 100, 100
- (b) 3, 6, 9
- (c) 1, 1, 5
- (d) 5, 10, 12
- Does there exist an equilateral triangle with sides 50, 50, 50? In general, does there exist an equilateral triangle of any sidelength? Justify your answer.
- For each of the following, give at least 5 possible values for the third length so there exists a triangle having these as sidelengths (decimal values could also be chosen):
- (a) 1, 100
- (b) 5, 5
- (c) 3, 7
Two Sides and Included Angle (SAS)
- Construct triangles for the following measurements where the angle is included between the sides:
- (a) 3 cm, 75°, 7 cm
- (b) 6 cm, 25°, 3 cm
- (c) 3 cm, 120°, 8 cm
Two Angles and Included Side (ASA)
- Construct triangles for the following measurements (two angles and the included side between them):
- (a) 75°, 5 cm, 75°
- (b) 25°, 3 cm, 60°
- (c) 120°, 6 cm, 30°
- For each of the following angles, find another angle for which a triangle is
- (a) possible,
- (b) not possible. Find at least two different angles for each category:
- (a) 30°
- (b) 70°
- (c) 54°
- (d) 144°
- Determine which of the following pairs can be the angles of a triangle and which cannot:
- (a) 35°, 150°
- (b) 70°, 30°
- (c) 90°, 85°
- (d) 50°, 150°
Angle Sum Property of Triangles
- Find the third angle of a triangle (using a parallel line) when two of the angles are:
- (a) 36°, 72°
- (b) 150°, 15°
- (c) 90°, 30°
- (d) 75°, 45°
- Can you construct a triangle all of whose angles are equal to 70°? If two of the angles are 70°, what would the third angle be? If all the angles in a triangle have to be equal, then what must its measure be? Explore and find out.
- Here is a triangle in which we know angle_B = angle_C and angle_A = 50°. Can you find angle_B and angle_C? [Figure shows triangle ABC with angle A = 50° at the top and equal angles at B and C.]
Types of Triangles and Altitudes
- Construct a triangle ABC with BC = 5 cm, AB = 6 cm, CA = 5 cm. Construct an altitude from A to BC.
- Construct a triangle TRY with RY = 4 cm, TR = 7 cm, angle_R = 140°. Construct an altitude from T to RY.
- Construct a right-angled triangle ABC with angle_B = 90°, AC = 5 cm. How many different triangles exist with these measurements? [Hint: Note that the other measurements can take any values. Take AC as the base. What values can angle_A and angle_C take so that the other angle is 90°?]
- Through construction, explore if it is possible to construct an equilateral triangle that is
- (i) right-angled
- (ii) obtuse-angled. Also construct an isosceles triangle that is
- (i) right-angled
- (ii) obtuse-angled.
Keep solving
More solutions in Ganita Prakash
01Large Numbers Around Us02Arithmetic Expressions03A Peek Beyond the Point04Expressions using Letter Numbers05Parallel and Intersecting Lines06Number Play08Working with Fractions09Geometric Twins10Operations with Integers11Finding Common Ground12Another Peek Beyond the Point13Connecting the Dots14Constructions and Tilings15Finding the Unknown
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More NCERT Solutions for Class 7
Read the A Tale of Three Intersecting Lines textbook chapter / PDF, or browse all NCERT Class 7 Mathematics solutions.
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