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Solutions

Overview

Step-by-step NCERT solutions for Thermodynamics (Chapter 5, NCERT Class 11 Chemistry) — every question and answer worked out in full, not just the final result. You can also read the Thermodynamics textbook chapter.

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What these solutions cover

All 22 questions in Thermodynamics are solved in the PDF. Here's what's inside, exercise by exercise:

Exercises

  1. Choose the correct answer. A thermodynamic state function is a quantity
    • (i) used to determine heat changes
    • (ii) whose value is independent of path
    • (iii) used to determine pressure volume work
    • (iv) whose value depends on temperature only.
  2. For the process to occur under adiabatic conditions, the correct condition is:
    • (i) DeltaT = 0
    • (ii) Deltap = 0
    • (iii) q = 0
    • (iv) w = 0
  3. The enthalpies of all elements in their standard states are:
    • (i) unity
    • (ii) zero
    • (iii) < 0
    • (iv) different for each element
  4. DeltaU of combustion of methane is -X kJ mol^-1. The value of DeltaH is
    • (i) = DeltaU
    • (ii) > DeltaU
    • (iii) < DeltaU
    • (iv) = 0
  5. The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are -890.3 kJ mol^-1, -393.5 kJ mol^-1, and -285.8 kJ mol^-1 respectively. Enthalpy of formation of CH4(g) will be
    • (i) -74.8 kJ mol^-1
    • (ii) -52.27 kJ mol^-1
    • (iii) +74.8 kJ mol^-1
    • (iv) +52.26 kJ mol^-1.
  6. A reaction, A + B -> C + D + q is found to have a positive entropy change. The reaction will be
    • (i) possible at high temperature
    • (ii) possible only at low temperature
    • (iii) not possible at any temperature
    • (v) possible at any temperature
  7. In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
  8. The reaction of cyanamide, NH2CN(s), with dioxygen was carried out in a bomb calorimeter, and DeltaU was found to be -742.7 kJ mol^-1 at 298 K. Calculate enthalpy change for the reaction at 298 K. NH2CN(g) + 3/2 O2(g) -> N2(g) + CO2(g) + H2O(l)
  9. Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol^-1 K^-1.
  10. Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0°C to ice at -10.0°C. DeltafusH = 6.03 kJ mol^-1 at 0°C. Cp[H2O(l)] = 75.3 J mol^-1 K^-1 Cp[H2O(s)] = 36.8 J mol^-1 K^-1
  11. Enthalpy of combustion of carbon to CO2 is -393.5 kJ mol^-1. Calculate the heat released upon formation of 35.2 g of CO2 from carbon and dioxygen gas.
  12. Enthalpies of formation of CO(g), CO2(g), N2O(g) and N2O4(g) are -110, -393, 81 and 9.7 kJ mol^-1 respectively. Find the value of DeltarH for the reaction: N2O4(g) + 3CO(g) -> N2O(g) + 3CO2(g)
  13. Given N2(g) + 3H2(g) -> 2NH3(g); DeltarH = -92.4 kJ mol^-1 What is the standard enthalpy of formation of NH3 gas?
  14. Calculate the standard enthalpy of formation of CH3OH(l) from the following data: CH3OH(l) + 3/2 O2(g) -> CO2(g) + 2H2O(l) ; DeltarH = -726 kJ mol^-1 C(graphite) + O2(g) -> CO2(g) ; DeltacH = -393 kJ mol^-1 H2(g) + 1/2 O2(g) -> H2O(l); DeltafH = -286 kJ mol^-1.
  15. Calculate the enthalpy change for the process CCl4(g) -> C(g) + 4 Cl(g) and calculate bond enthalpy of C-Cl in CCl4(g). DeltavapH(CCl4) = 30.5 kJ mol^-1 DeltafH(CCl4) = -135.5 kJ mol^-1 DeltaaH(C) = 715.0 kJ mol^-1 (enthalpy of atomisation) DeltaaH(Cl2) = 242 kJ mol^-1
  16. For an isolated system, DeltaU = 0, what will be DeltaS?
  17. For the reaction at 298 K, 2A + B -> C DeltaH = 400 kJ mol^-1 and DeltaS = 0.2 kJ K^-1 mol^-1 At what temperature will the reaction become spontaneous considering DeltaH and DeltaS to be constant over the temperature range.
  18. For the reaction, 2 Cl(g) -> Cl2(g), what are the signs of DeltaH and DeltaS?
  19. For the reaction 2 A(g) + B(g) -> 2D(g) DeltaU = -10.5 kJ and DeltaS = -44.1 J K^-1. Calculate DeltaG for the reaction, and predict whether the reaction may occur spontaneously.
  20. The equilibrium constant for a reaction is 10. What will be the value of DeltaG? R = 8.314 J K^-1 mol^-1, T = 300 K.
  21. Comment on the thermodynamic stability of NO(g), given 1/2 N2(g) + 1/2 O2(g) -> NO(g); DeltarH = 90 kJ mol^-1 NO(g) + 1/2 O2(g) -> NO2(g); DeltarH = -74 kJ mol^-1
  22. Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. DeltafH = -286 kJ mol^-1.
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