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Class 10 Mathematics
Chapter 8 Solutions — Introduction to Trigonometry
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Step-by-step NCERT solutions for Introduction to Trigonometry (Chapter 8, CBSE Class 10 Mathematics) — the full working for every question, not just the final answer. You can also read the Introduction to Trigonometry textbook chapter.
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What these solutions cover
All 19 questions in Introduction to Trigonometry are solved in the PDF. Here's what's inside, exercise by exercise:
Trigonometric Ratios
- In △ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:
- (i) sin A, cos A
- (ii) sin C, cos C
- In Fig. 8.13, find tan P – cot R. (Triangle PQR right-angled at Q, with PQ = 12 cm, QR = 5 cm, PR = 13 cm)
- If sin A = 3/4, calculate cos A and tan A.
- Given 15 cot A = 8, find sin A and sec A.
- Given sec θ = 13/12, calculate all other trigonometric ratios.
- If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
- If cot θ = 7/8, evaluate:
- (i) (1 + sin θ)(1 – sin θ) / [(1 + cos θ)(1 – cos θ)]
- (ii) cot² θ
- If 3 cot A = 4, check whether (1 – tan²A) / (1 + tan²A) = cos²A – sin²A or not.
- In triangle ABC, right-angled at B, if tan A = 1/√3, find the value of:
- (i) sin A cos C + cos A sin C
- (ii) cos A cos C – sin A sin C
- In △PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
- State whether the following are true or false. Justify your answer.
- (i) The value of tan A is always less than 1.
- (ii) sec A = 12/5 for some value of angle A.
- (iii) cos A is the abbreviation used for the cosecant of angle A.
- (iv) cot A is the product of cot and A.
- (v) sin θ = 4/3 for some angle θ.
Trigonometric Ratios of Specific Angles
- Evaluate the following:
- (i) sin 60° cos 30° + sin 30° cos 60°
- (ii) 2 tan² 45° + cos² 30° – sin² 60°
- (iii) cos 45° / (sec 30° + cosec 30°)
- (iv) (sin 30° + tan 45° – cosec 60°) / (sec 30° + cos 60° + cot 45°)
- (v) (5 cos² 60° + 4 sec² 30° – tan² 45°) / (sin² 30° + cos² 30°)
- Choose the correct option and justify your choice:
- (i) 2 tan 30°/(1 – tan² 30°) = (A) sin 60° (B) cos 60° (C) tan 60° (D) sin 30°
- (ii) (1 – tan² 45°)/(1 + tan² 45°) = (A) tan 90° (B) 1 (C) sin 45° (D) 0
- (iii) sin 2A = 2 sin A is true when A = (A) 0° (B) 30° (C) 45° (D) 60°
- (iv) 2 tan 30°/(1 + tan² 30°) = (A) cos 60° (B) sin 60° (C) tan 60° (D) sin 30°
- If tan (A + B) = √3 and tan (A – B) = 1/√3; 0° < A + B ≤ 90°; A > B, find A and B.
- State whether the following are true or false. Justify your answer.
- (i) sin (A + B) = sin A + sin B.
- (ii) The value of sin θ increases as θ increases.
- (iii) The value of cos θ increases as θ increases.
- (iv) sin θ = cos θ for all values of θ.
- (v) cot A is not defined for A = 0°.
Trigonometric Identities
- Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.
- Write all the other trigonometric ratios of angle A in terms of sec A.
- Choose the correct option. Justify your choice.
- (i) 9 sec²A – 9 tan²A = (A) 1 (B) 9 (C) 8 (D) 0
- (ii) (1 + tan θ + sec θ)(1 + cot θ – cosec θ) = (A) 0 (B) 1 (C) 2 (D) –1
- (iii) (sec A + tan A)(1 – sin A) = (A) sec A (B) sin A (C) cosec A (D) cos A
- (iv) (1 + tan²A) / (1 + cot²A) = (A) sec²A (B) –1 (C) cot²A (D) tan²A
- Prove the following identities, where the angles involved are acute angles for which the expressions are defined:
- (i) (cosec θ – cot θ)² = (1 – cos θ) / (1 + cos θ)
- (ii) cos A / (1 + sin A) + (1 + sin A) / cos A = 2 sec A
- (iii) tan θ / (1 – cot θ) + cot θ / (1 – tan θ) = 1 + sec θ cosec θ [Hint: Write the expression in terms of sin θ and cos θ]
- (iv) (1 + sec A) / sec A = sin²A / (1 – cos A)…
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