Summary
Class 11 Physics Chapter 3 covers motion in a plane using vector algebra, including projectile motion and uniform circular motion. Download the free NCERT PDF.
Motion in a Plane teaches how to describe 2D motion using vectors. The chapter begins with scalars and vectors, covering vector operations (addition, subtraction, multiplication), resolution of vectors using unit vectors, and analytical methods for vector addition. It then applies these to motion in a plane with constant acceleration, deriving kinematic equations in component form. Projectile motion is analyzed as two independent 1D motions: constant horizontal velocity and vertical motion under gravity. The path follows a parabolic trajectory, with formulas for maximum height, time of flight, and horizontal range. Finally, uniform circular motion explains centripetal acceleration (v²/R) directed toward the center, angular speed (ω = v/R), and the relationship between period, frequency, and linear velocity.
Key points & formulas
- 01Vectors have magnitude and direction; scalars have magnitude only. Vector addition follows triangle or parallelogram law, is commutative (A+B=B+A) and associative.
- 02Any vector can be resolved into components along perpendicular axes using unit vectors î and ĵ. Components relate to magnitude and direction angle by Ax = A cos θ, Ay = A sin θ.
- 03Motion in a plane is treated as two independent 1D motions. Using r = r₀ + v₀t + ½at² separately for x and y directions simplifies 2D kinematics.
- 04Projectile motion path is parabolic: y = (tan θ₀)x − gx²/(2v₀² cos² θ₀). Maximum height is hm = (v₀ sin θ₀)²/(2g), reached at time tm = v₀ sin θ₀/g.
- 05Horizontal range of projectile is R = v₀² sin 2θ₀/g, maximum when θ₀ = 45°. Time of flight is Tf = 2v₀ sin θ₀/g.
- 06In uniform circular motion, acceleration (centripetal) always points toward center with magnitude ac = v²/R = ω²R, where ω = v/R is angular speed. Velocity remains tangent to the circle.
Frequently asked questions
01What is the difference between displacement and path length in motion?
Displacement is the straight-line distance from initial to final position, independent of the actual path. Path length is the total distance traveled along the actual trajectory. They are equal only if motion is in a straight line without direction change. In all other cases, path length is greater than or equal to displacement magnitude.
02How do you find the maximum height and time to reach it for a projectile?
Maximum height is hm = (v₀ sin θ₀)²/(2g), where v₀ is initial velocity and θ₀ is launch angle. The time to reach maximum height is tm = v₀ sin θ₀/g. At maximum height, the vertical component of velocity (vy) becomes zero; only horizontal velocity remains.
03Why is the acceleration in uniform circular motion always perpendicular to velocity?
In uniform circular motion, speed is constant but direction continuously changes. Acceleration measures the rate of change of velocity. Since the magnitude is constant, acceleration only changes the direction of velocity, not its magnitude. This requires acceleration perpendicular to velocity (toward center), giving centripetal acceleration ac = v²/R directed radially inward.
04Is the NCERT Class 11 Physics Chapter 3 PDF free to download?
Yes, the NCERT Class 11 Physics Chapter 3 PDF is completely free to download. NCERT textbooks are published by India's National Council of Educational Research and Training as open educational resources for all students.
More chapters in Physics Part I
This is the complete Physics Part I Chapter 3 as published by NCERT — every diagram, solved example, and exercise included, free. Browse all NCERT Class 11 textbooks.
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